Mathematician & occasional comedian here.
If something belongs in both sets, then it goes in the intersection ONLY. Which is where Moose put it.
So this joke is certifiably Mathematically Correct™.
Not that that matters.
It's a nice joke.
Enjoy the nice joke.
If something belongs in both sets, then it goes in the intersection ONLY. Which is where Moose put it.
So this joke is certifiably Mathematically Correct™.
Not that that matters.
It's a nice joke.
Enjoy the nice joke.
Comments
Bonobo(e) is the union of the two, not the intersection.
A + B - (intersection of A and B) = Union
Bono + Oboe - o = Bonoboe
(Yes, yes, fun at parties, etc. etc.)
Such as (to use a very obvious example)...
A = [has BONO sound]
and
B = [Has OBO sound]
then
BONO is in set A only
OBOE is in set B only
BONOBO is in both sets A and B
Which in this case is
A + B - int(A,B) = union(A,B)
becoming
2 + 2 - 1 = 3