No, but.. without an X operator the high overlap of |ψ⟩ with Φ(x)|0⟩ doesn't translate into any statement about likelihood to detect the particle ψ near x..
I do agree that existence of an X is too much to ask in QFT. But we need something, and I'm trying to formulate it properly..
I do agree that existence of an X is too much to ask in QFT. But we need something, and I'm trying to formulate it properly..
Comments
So that quantum optics experiments in two countries can ignore each other. And even different arms of the same experiment can ignore each other (you often hear "photon went down this arm of the device")
QFT is an inevitable consequence of the conjunction of
1. QM
2. SR
3. cluster decomposition, i.e. exactly this asymptotic condition