With the subspace topology, a subset of a totally orderable space need not be totally orderable, even though we are allowed to rearrange the order of the points in the subset.
The real subpace [0,1) U [2,3] is NOT a counterexample, however the subspace (0,1) U [2,3] is NOT totally orderable.
The real subpace [0,1) U [2,3] is NOT a counterexample, however the subspace (0,1) U [2,3] is NOT totally orderable.
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